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JEE Mains · Maths · STD 12 - 10. vector algebra

मान लीजिए कि सदिश \(\vec{a} = -\hat{i} + \hat{j} + 3\hat{k}\) और \(\vec{b} = \hat{i} + 3\hat{j} + \hat{k}\) हैं। कुछ \(\lambda, \mu \in \mathbb{R}\) के लिए, मान लीजिए \(\vec{c} = \lambda \vec{a} + \mu \vec{b}\)। यदि \(\vec{c} \cdot (3\hat{i} - 6\hat{j} + 2\hat{k}) = 10\) और \(\vec{c} \cdot (\hat{i} + \hat{j} + \hat{k}) = -2\), तो \(|\vec{c}|^2\) के बराबर है:

  1. A \(8\)
  2. B \(12\)
  3. C \(14\)
  4. D \(15\)
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Answer & Solution

Correct Answer

(B) \(12\)

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Detailed explanation

दिया है \(\vec{a} = -\hat{i} + \hat{j} + 3\hat{k}\) और \(\vec{b} = \hat{i} + 3\hat{j} + \hat{k}\)। सदिश \(\vec{c}\) इस प्रकार दिया गया है: \(\vec{c} = \lambda \vec{a} + \mu \vec{b} = (-\lambda + \mu)\hat{i} + (\lambda + 3\mu)\hat{j} + (3\lambda + \mu)\hat{k}\) पहली शर्त…
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