JEE Mains · Maths · STD 12 - 13. probability
A person throws two fair dice. He wins \(Rs.\, 15\) for throwing a doublet (same numbers on the two dice), wins \(Rs.\,12\) when the throw results in the sum of \(9\), and loses \(Rs.\, 6\) for any other outcome on the throw. Then the expected gain/loss (in \(Rs.\)) of the person is
- A \(\frac{1}{4}\) loss
- B \(2\) gain
- C \(\frac{1}{2}\) gain
- D \(\frac{1}{2}\) loss
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\) loss
Step-by-step Solution
Detailed explanation
\(Coin\) \(+15\) \(+12\) \(-6\) \(Probability\) \(\frac{6}{{36}}\) \(\frac{4}{{36}}\) \(\frac{{26}}{{36}}\) Probability of doublet \(=\frac{6}{36}\) Probability of sum of \(9=\frac{4}{36}\) Other probability \(=\frac{26}{36}\) Expected gain/loss…
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