JEE Mains · Maths · STD 12 - 2. inverse trigonometric function
The value of \(\cot ^{-1}\left(\frac{\sqrt{1+\tan ^2(2)}-1}{\tan (2)}\right)-\cot ^{-1}\) \(\left(\frac{\sqrt{1+\tan ^2\left(\frac{1}{2}\right)}+1}{\tan \left(\frac{1}{2}\right)}\right) \text { is equal to }\)
- A \(\pi-\frac{5}{4}\)
- B \(\pi-\frac{3}{2}\)
- C \(\pi+\frac{3}{2}\)
- D \(\pi+\frac{5}{2}\)
Answer & Solution
Correct Answer
(A) \(\pi-\frac{5}{4}\)
Step-by-step Solution
Detailed explanation
\(\cot ^{-1}\left(\frac{|\sec 2|-1}{\tan 2}\right)-\cot ^{-1}\left(\frac{\left|\sec \frac{1}{2}\right|+1}{\tan \frac{1}{2}}\right)\)…
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