JEE Mains · Maths · STD 11 - Trigonometrical equations
The number of solutions of the equation \(2 \theta-\cos ^{2} \theta+\sqrt{2}=0\) is \(R\) is equal to
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(2 \theta-\cos ^{2} \theta+\sqrt{2}=0\) \(\Rightarrow \cos ^{2} \theta=2 \theta+\sqrt{2}\) \(y=2 \theta+\sqrt{2}\) Both graphs intersect at one point.
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