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JEE Mains · Maths · STD 11 - 1. set theory

Let \(\bigcup \limits_{i=1}^{50} X_{i}=\bigcup \limits_{i=1}^{n} Y_{i}=T\) where each \(X_{i}\) contains \(10\) elements and each \(Y_{i}\) contains \(5\) elements. If each element of the set \(T\) is an element of exactly \(20\) of sets \(X_{i}\) 's and exactly \(6\) of sets \(Y_{i}\) 's, then \(n\) is equal to

  1. A \(45\)
  2. B \(15\)
  3. C \(50\)
  4. D \(30\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(30\)

Step-by-step Solution

Detailed explanation

\(n \left( X _{ i }\right)=10 . \underset{ i =1}{ U } X _{ i }= T , \Rightarrow n ( T )=500\) each element of \(T\) belongs to exactly 20 elements of \(X _{ i } \Rightarrow \frac{500}{20}=25\) distinct elements so \(\frac{5 n}{6}=25 \Rightarrow n=30\)
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