JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If the line \(\alpha x+2y=1\), where \(\alpha\in\mathbb{R}\), does not meet the hyperbola \(x^{2}-9y^{2}=9\), then a possible value of \(\alpha\) is:
- A 0.6
- B 0.8
- C 0.5
- D 0.7
Answer & Solution
Correct Answer
(B) 0.8
Step-by-step Solution
Detailed explanation
\(y=\frac{1-\alpha x}{2}\) Put this in equation of hyperbola \(\therefore x^2-9\left(\frac{1-\alpha x}{2}\right)^2=9\) \(\begin{array}{l}\left(4-9 \alpha^2\right) x ^2+18 \alpha x -45=0 \\ \because \text { line does not intersect hyperbola } \\ \therefore D <0\end{array}\)…
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