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JEE Mains · Maths · STD 11 - 9. straight line

Let \(m_{1}, m_{2}\) be the slopes of two adjacent sides of a square of side a such that \(a^{2}+11 a+3\left(m_{2}^{2}+m_{2}^{2}\right)=220\). If one vertex of the square is \((10(\cos \alpha-\sin \alpha), 10(\sin \alpha+\cos \alpha))\), where \(\alpha \in\left(0, \frac{\pi}{2}\right)\) and the equation of one diagonal is \((\cos \alpha-\sin \alpha) x +(\sin \alpha+\cos \alpha) y =10\), then  \(72 \left(\sin ^{4} \alpha+\cos ^{4} \alpha\right)+a^{2}-3 a+13\) is equal to.

  1. A \(119\)
  2. B \(128\)
  3. C \(145\)
  4. D \(155\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(128\)

Step-by-step Solution

Detailed explanation

\(m_{1} m_{2}=-1\) \(a^{2}+11 a+3\left(m_{1}^{2}+\frac{1}{m_{1}^{2}}\right)=220\) Eq. of \(AC\) \(AC =(\cos \alpha-\sin \alpha)+(\sin \alpha+\cos \alpha) y =10\) \(BD =(\sin \alpha-\cos \alpha) x +(\sin \alpha-\cos \alpha) y =0\)…
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