JEE Mains · Maths · STD 11 - 9. straight line
Let \( A(1,2) \) and \( C(-3,-6) \) be two diagonally opposite vertices of a rhombus, whose sides AD and BC are parallel to the line \( 7x-y=14 \). If \( B(\alpha, \beta) \) and \( D(\gamma, \delta) \) are the other two vertices, then \( |\alpha+\beta+\gamma+\delta| \) is equal to:
- A 9
- B 3
- C 6
- D 1
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
Given the points of B and D are \((\alpha, \beta)\) and \((\gamma, \delta)\) and mid point of A and C is \((-1,-2)\) So \(\frac{\alpha+\gamma}{2}=-1\) and \(\frac{\beta+\delta}{2}=-2\) \(|\alpha+\gamma+\beta+\delta|=6\)
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