JEE Mains · Maths · STD 11 - 12. limits
\(\mathop {{\rm{lim}}}\limits_{x \to 0} \frac{{{\rm{sin}}\left( {\pi {{\cos }^2}x} \right)}}{{{x^2}}} = \)
- A \( - \pi \)
- B \(\;\pi \)
- C \(\frac{\pi }{2}\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(\;\pi \)
Step-by-step Solution
Detailed explanation
\(\mathop {lim}\limits_{x \to 0} \frac{{\sin \left( {\pi {{\cos }^2}x} \right)}}{{{x^2}}}\) \( = \mathop {lim}\limits_{x \to 0} \frac{{\sin \left( {\pi \left( {1 - {{\sin }^2}x} \right)} \right)}}{{{x^2}}}\)…
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