JEE Mains · Maths · STD 11 - 6. permutation and combination
In an examination of Mathematics paper, there are \(20\) questions of equal marks and the question paper is divided into three sections : \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\). A student is required to attempt total \(15\) questions taking at least \(4\) questions from each section. If section \(A\) has \(8\) questions, section \(\mathrm{B}\) has \(6\) questions and section \(\mathrm{C}\) has \(6\) questions, then the total number of ways a student can select \(15\) questions is
- A \(11370\)
- B \(11376\)
- C \(11375\)
- D \(11350\)
Answer & Solution
Correct Answer
(B) \(11376\)
Step-by-step Solution
Detailed explanation
If \(4\) questions from each section are selected Remaining \(3\) questions can be selected either in \((1,1,1)\) or \((3,0,0)\) or \((2,1,0)\) \(\therefore\) Total ways…
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