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JEE Mains · Maths · STD 11 - 6. permutation and combination

Number of ways of arranging \(8\) identical books into \(4\) identical shelves where any number of shelves may remain empty is equal to

  1. A \(18\)
  2. B \(16\)
  3. C \(12\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(15\)

Step-by-step Solution

Detailed explanation

\(3\) Shelf empty \(:(8,0,0,0) \rightarrow 1\) way \(2\) shelf empty : \(\left.\begin{array}{c}(7,1,0,0) \\ (6,2,0,0) \\ (5,3,0,0) \\ (4,4,0,0)\end{array}\right] \rightarrow 4\) ways \(1\) shelf empty:…
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