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JEE Mains · Maths · STD 11 - 8. sequence and series

Let \(a, b, c > 1, a^3, b^3\) and \(c^3\) be in \(A.P.\), and \(\log _a b\), \(\log _c a\) and \(\log _b c\) be in G.P. If the sum of first \(20\) terms of an \(A.P.\), whose first term is \(\frac{a+4 b+c}{3}\) and the common difference is \(\frac{a-8 b+c}{10}\) is \(-444\), then abc is equal to

  1. A \(343\)
  2. B \(216\)
  3. C \(\frac{343}{8}\)
  4. D \(\frac{125}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(216\)

Step-by-step Solution

Detailed explanation

As \(a ^3, b^3, c^3\) be in \(A.P.\) \(\rightarrow a^3+c^3=2 b^3\) \(\log _{ a }^{ b }, \log _{ c }^{ a }, \log _{ b }^{ c }\) are in \(G.P.\) \(\therefore \frac{\log b }{\log a } \cdot \frac{\log c}{\log b}=\left(\frac{\log a}{\log c}\right)^2\)…
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