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JEE Mains · Maths · STD 11 - 9. straight line

Let the line \(x+y=1\) meet the axes of \(x\) and \(y\) at A and B, respectively. A right angled triangle AMN is inscribed in the triangle OAB , where O is the origin and the points M and N lie on the lines \(O B\) and \(A B\), respectively. If the area of the triangle \(A M N\) is \(\frac{4}{9}\) of the area of the triangle \(O A B\) and AN : NB \(=\lambda: 1\), then the sum of all possible value(s) of is \(\lambda\) :

  1. A 2
  2. B \(\frac{5}{2}\)
  3. C \(\frac{1}{2}\)
  4. D \(\frac{13}{6}\)
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Correct Answer

(A) 2

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\(\begin{aligned} & \text {Area of } \triangle \mathrm{AOB}=\frac{1}{2} \\ & \text {Area of } \triangle \mathrm{AMN}=\frac{4}{9} \times \frac{1}{2}=\frac{2}{9} \end{aligned}\) Equation of AB is \(\mathrm{x}+\mathrm{y}=1\)…
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