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JEE Mains · Maths · STD 12 - 13. probability

If the mean of the following probability distribution of a random variable \(X\);
\(X\)\(0\)\(2\)\(4\)\(6\)\(8\)
\(P(X)\)\(a\)\(2a\)\(a+b\)\(2b\)\(3b\)
is \(\frac{46}{9}\) , then the variance of the distribution is

  1. A \(\frac{581}{81}\)
  2. B \(\frac{566}{81}\)
  3. C  \(\frac{173}{27}\)
  4. D \(\frac{151}{27}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{566}{81}\)

Step-by-step Solution

Detailed explanation

\( \sum P_i=1 \) \( a+2 a+a+b+2 b+3 b=1 \) \( 4 a+6 b=1 \).................(\(i\)) \( E(x)=\text { mean }=\frac{46}{9}\)…
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