JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The sum of all real values of \(x\) satisfying the equation \({\left( {{x^2} - 5x + 5} \right)^{{x^2} + 4x - 60}} = 1\) is ;
- A \(6\)
- B \(5\)
- C \(3\)
- D \(-4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(x^{2}-5 x+5=1\) \(\Rightarrow x=1,4\) \(x^{2}-5 x+5=-1\) \(\Rightarrow x=2,3\) but \(3\) is rejected \(x^{2}+4 x-60=0\) \(\Rightarrow x=-10,6\) \(\operatorname{sum}=3\)
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