JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(X Y\) is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration \(c_1\) and \(c_2\left(c_1 \gt c_2\right) \mathrm{mol} \mathrm{L}^{-1}\). For the reverse osmosis to take place identify the correct condition
(Here \(p_1\) and \(p_2\) are pressures applied on chamber 1 and 2)
(A) Membrane/Partition; Cellophane, \(\mathrm{p}_1 \gt \pi\)
(B) Membrane/Partition ; Porous. \(\mathrm{p}_2 \gt \pi\)
(C) Membrane/Partition ; Parchment paper, \(\mathrm{p}_1 \gt \pi\)
(D) Membrane/Partition : Cellophane, \(\mathrm{p}_2 \gt \pi\)
Choose the correct answer from the option given below :
- A B and D only
- B A and D only
- C A and C only
- D C only
Answer & Solution
Correct Answer
(C) A and C only
Step-by-step Solution
Detailed explanation
Normal osmosis occurs from (2) to (1) For reverse osmosis from (1) to (2) Pressure : \(\mathrm{P}_1 \gt \pi\) \(\therefore\) Answer [A & C] only
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