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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
When \(0.01\,mol\) of an organic compound containing \(60\,\%\) carbon was burnt completely, \(4.4\,g\) of \(CO _2\) was produced. The molar mass of compound is \(.........g\,mol ^{-1}\) (Nearest integer)
- A \(100\)
- B \(50\)
- C \(200\)
- D \(150\)
Answer & Solution
Correct Answer
(C) \(200\)
Step-by-step Solution
Detailed explanation
Let \(M\) is the molar mass of the compound \(( g / mol )\) mass of compound \(=0.01\,M\,gm\) \(\text { mass of carbon }=0.01 M \times \frac{60}{100}\) \(\text { moles of carbon }=\frac{0.01 M }{12} \times \frac{60}{100}\) moles of \(CO _2\) from combustion \(=\frac{4.4}{44}=\)…
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