JEE Mains · Chemistry · STD 12 - p -Block elements - ll
The number of bridged oxygen atoms present in compound \(B\) formed from the following reactions is \(Pb \left( NO _{3}\right)_{2} \stackrel{673 K }{\longrightarrow} A + PbO + O _{2}\) \(A \stackrel{\text { Dimerise }}{\longrightarrow} B\)
- A \(0\)
- B \(1\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(Pb \left( NO _{3}\right)_{2} \frac{\Delta}{673 K } PbO + NO _{2}+ O _{2}\) \(2 NO _{2} \stackrel{\text { Dimerise }}{\longrightarrow} N _{2} O _{4}\)
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