JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: \(Mn =25 ; Fe =26\) ) \((A)\) \(\left[ FeF _{6}\right]^{3-}\) \((B)\) \(\left[ Fe ( CN )_{6}\right]^{3-}\) \((C)\) \(\left[ MnCl _{6}\right]^{3-}\) (high spin) \((D)\) \(\left[ Mn ( CN )_{6}\right]^{3-}\)
- A \(A \,<\, B\, <\, D \,< \,C\)
- B \(B \,<\, D \,< \,C\, <\, A\)
- C \(A \,<\, C\, <\, D\, < \,B\)
- D \(B \,< \,D\, < \,A \,<\, C\)
Answer & Solution
Correct Answer
(B) \(B \,<\, D \,< \,C\, <\, A\)
Step-by-step Solution
Detailed explanation
\((A)\) \(\left[ FeF _{6}\right]^{3-}\) \(Fe ^{+3} \rightarrow 3 d ^{5} 4 s ^{0}\) \(n =5\) \((B)\) \(\left[ Fe ( CN )_{6}\right]^{3-}\) \(Fe ^{+3} \rightarrow 3 d ^{5} 4 s ^{0}\) \(n =1\) \((C)\) \(\left[ MnCl _{6}\right]^{3-}\) \(Mn ^{+3} \rightarrow 3 d ^{4} 4 s ^{0}\)…
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