JEE Mains · Chemistry · STD 11 - 2. structure of atom
The wavelength of an electron of kinetic energy \(4.50 \times 10^{-29}\,J\) is \(\ldots . . \times 10^{-5}\,m\). (Nearest integer)Given : mass of electron is \(9 \times 10^{-31}\,kg , h =6.6 \times\) \(10^{-34}\,J s\)
- A \(6\)
- B \(5\)
- C \(4\)
- D \(7\)
Answer & Solution
Correct Answer
(D) \(7\)
Step-by-step Solution
Detailed explanation
\(\lambda_{ d }=\frac{ h }{ mv }=\frac{ h }{\sqrt{2 mKE }}=\frac{6.6 \times 10^{-34}}{\sqrt{2 \times 9 \times 10^{-31} \times 4.5 \times 10^{-29}}}\) \(=\frac{6.6 \times 10^{-34}}{\sqrt{9^2 \times 10^{-60}}}\)…
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