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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2023
  • Easy
  • Numerical

The position of a particle related to time is given by \(x =\left(5 t ^2-4 t +5\right) m\). The magnitude of velocity of the particle at \(t=2\,s\) will be \(...........ms^{-1}\)

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Answer & Solution

Correct Answer

(C) \(16\)

Step-by-step Solution

Detailed explanation

\(x=5 t^2-4 t+5\)

\(v=10 t-4\)

\(\text { At } t=2 s \quad v=16\,m / s\)

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