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JEE Mains · Physics · STD 11 - 2. motion in straight line

The position of a particle related to time is given by \(x =\left(5 t ^2-4 t +5\right) m\). The magnitude of velocity of the particle at \(t=2\,s\) will be \(...........ms^{-1}\)

  1. A \(10\)
  2. B \(14\)
  3. C \(16\)
  4. D \(06\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(16\)

Step-by-step Solution

Detailed explanation

\(x=5 t^2-4 t+5\) \(v=10 t-4\) \(\text { At } t=2 s \quad v=16\,m / s\)
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