JEE Mains · Physics · STD 11 - 2. motion in straight line
The position of a particle related to time is given by \(x =\left(5 t ^2-4 t +5\right) m\). The magnitude of velocity of the particle at \(t=2\,s\) will be \(...........ms^{-1}\)
- A \(10\)
- B \(14\)
- C \(16\)
- D \(06\)
Answer & Solution
Correct Answer
(C) \(16\)
Step-by-step Solution
Detailed explanation
\(x=5 t^2-4 t+5\) \(v=10 t-4\) \(\text { At } t=2 s \quad v=16\,m / s\)
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