JEE Mains · Chemistry · STD 11 - 7. Redox reactions
The volume, in \(mL ,\) of \(0.02\, M K _{2} Cr _{2} O _{7}\) solution required to react with \(0.288\, g\) of ferrous oxalate in acidic medium is........ (Molar mass of \(Fe =56\, g\, mol ^{-1}\) )
- A \(55\)
- B \(52\)
- C \(60\)
- D \(50\)
Answer & Solution
Correct Answer
(D) \(50\)
Step-by-step Solution
Detailed explanation
\(K _{2} Cr _{2} O _{7}+ FeC _{2} O _{4} \longrightarrow Cr ^{+3}+ Fe ^{+3}+ CO _{2}\) \(n=6 \quad \quad n=3\) \(\frac{0.02 \times 6 \times V ( mL )}{1000}=\frac{0.288}{144} \times 3\) \(\Rightarrow \quad V =50 mL\)
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