JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The potential for the given half cell at \(298 \mathrm{~K}\) is \((-)\) _______ \(\times 10^{-2} \mathrm{~V}\). \(2 \mathrm{H}_{(\mathrm{aq})}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2(\mathrm{~g})\) \({\left[\mathrm{H}^{+}\right]=1 \mathrm{M}, \mathrm{P}_{\mathrm{H}_2}=2 \mathrm{~atm}}\) (Given: \(2.303 \mathrm{RT} / \mathrm{F}=0.06 \mathrm{~V}, \log 2=0.3\) )
- A \(0\)
- B \(1\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(E=E_{\mathrm{H}^{+} / \mathrm{H}_2}^0-\frac{0.06}{2} \log \frac{\mathrm{P}_{\mathrm{H}_2}}{\left[\mathrm{H}^{+}\right]^2}\) \(\mathrm{E}=0.00-\frac{0.06}{2} \log \frac{2}{[1]^2}\) \(E=-0.03 \times 0.3=-0.9 \times 10^{-2} \mathrm{~V}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- The logarithm of equilibrium constant for the reaction \(Pd ^{2+}+4 Cl ^{-} \rightleftharpoons PdCl _4^{2-}\) is (Nearest integer) Given \(: \frac{2.303 RT }{ F }=0.06 V\) \(Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V\) \(PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )\) \(E ^{\circ}=0.65\,V\)JEE Mains 2023 Medium
- Which of the following compounds show colour due to \(d-d\) transition?JEE Mains 2024 Hard
- Identify the incorrect statement from the following.JEE Mains 2022 Medium
- For the reaction, \(2S{O_2}{\kern 1pt} (g)\, + \,{O_2}\,(g)\, \to \,2S{O_3}\,(g)\) \({\Delta _H}\, = \, - 57.2\,kJ\,mo{l^{ - 1}}\) and \({K_C} = 1.7\, \times \,{10^{16}}\) Which of the following statement is \(INCORRECT\) ?JEE Mains 2019 Medium
- A solution is prepared by dissolving \(0.6\, g\) of urea (molar mass \(= 60\, g\, mol^{-1}\)) and \(1.8\, g\) of glucose (molar mass \(= 180\, g\, mol^{-1}\)) in \(100\, mL\) of water at \(27\,^oC\). The osmotic pressure of the solution is : ............. \(\mathrm{atm}\) \((R = 0.08206\, L\, atm\, K^{-1}\, mol^{-1})\)JEE Mains 2019 Hard
- An exothermic reaction \(X \rightarrow Y\) has an activation energy \(30\, kJ \,mol ^{-1}\). If energy change \(\Delta E\) during the reaction is \(-20\, kJ ,\) then the activation energy for the reverse reaction in \(kJ\) is \(...\).(Integer answer)JEE Mains 2021 Easy
More PYQs from JEE Mains
- The number of ways, \(16\) identical cubes, of which \(11\) are blue and rest are red, can be placed in a row so that between any two red cubes there should be at least \(2\) blue cubes, isJEE Mains 2022 Hard
- Which of the following is a set of green house gases ?JEE Mains 2017 Hard
- If the letters of the word \(MATHS\) are permuted and all possible words so formed are arranged as in a dictionary with serial numbers, then the serial number of the word \(THAMS\) isJEE Mains 2023 Hard
- Given are two statements one is labelled as Assertion \(A\) and other is labelled as Reason \(R\). Assertion \(A\) :Magnesium can reduce \(Al _{2} O _{3}\) at a temperature below \(1350^{\circ} C\), while above \(1350^{\circ} C\) aluminium can reduce \(MgO\). Reason \(R\) : The melting and boiling points of magnesium are lower than those of aluminium. In light of the above statements. choose most appropriate answer from the options given belowJEE Mains 2022 Medium
- Which of the following electronegativity order is incorrect?JEE Mains 2025 Medium
- The probability that a randomly chosen \(2 \times 2\) matrix with all the entries from the set of first \(10\) primes, is singular, is equal toJEE Mains 2022 Hard