JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The pH of a solution obtained by mixing \(5\) mL of \(0.1\) M \(NH_4OH\) solution with \(250\) mL of \(0.1\) M \(NH_4Cl\) solution is _____ \(\times 10^{-2}\). (Nearest integer)
Given: \(pK_b(NH_4OH) = 4.74\)
\(\log 2 = 0.30\)
\(\log 3 = 0.48\)
\(\log 5 = 0.70\)
- A 856
- B 756
- C 956
- D 656
Answer & Solution
Correct Answer
(B) 756
Step-by-step Solution
Detailed explanation
The given mixture forms a basic buffer solution. Millimoles of base \(NH_4OH = 5 \times 0.1 = 0.5\) mmol Millimoles of salt \(NH_4Cl = 250 \times 0.1 = 25\) mmol Using the Henderson-Hasselbalch equation for a basic buffer:…
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