JEE Mains · Physics · STD 11 - Transmission of heat
- JEE Mains 2019
- Hard
- MCQ
Temperature difference of \(120\,^oC\) is maintained between two ends of a uniform rod \(AB\) of length \(2L\). Another bent rod \(PQ\), of same cross-section as \(AB\) and length \(\frac{{3L}}{2}\), is connected across \(AB\) (See figure). In steady state, temperature difference between \(P\) and \(Q\) will be close to .......... \(^oC\)

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Answer & Solution
Correct Answer
(A) \(45\)
Step-by-step Solution
Detailed explanation
\({T_A} - {T_B} = \frac{{{T_1} - {T_2}}}{{\frac{{8R}}{5}}} \times \frac{{3R}}{5} = \frac{3}{8} \times 120 = 45\)


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