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JEE Mains · Physics · STD 11 - Transmission of heat
  • JEE Mains 2019
  • Hard
  • MCQ

Temperature difference of \(120\,^oC\) is maintained between two ends of a uniform rod \(AB\) of length \(2L\). Another bent rod \(PQ\), of same cross-section as \(AB\) and length \(\frac{{3L}}{2}\),  is connected across \(AB\) (See figure). In steady state, temperature difference between \(P\) and \(Q\) will be close to .......... \(^oC\)

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Answer & Solution

Correct Answer

(A) \(45\)

Step-by-step Solution

Detailed explanation

\({T_A} - {T_B} = \frac{{{T_1} - {T_2}}}{{\frac{{8R}}{5}}} \times \frac{{3R}}{5} = \frac{3}{8} \times 120 = 45\)