JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
The number of terminal oxygen atoms present in the product \(B\) obtained from the following reaction is \(....\) \(FeCr _{2} O _{4}+ Na _{2} CO _{3}+ O _{2} \rightarrow A + Fe _{2} O _{3}+ CO _{2}\) \(A + H ^{+} \rightarrow B + H _{2} O + Na ^{+}\)
- A \(6\)
- B \(54\)
- C \(9\)
- D \(81\)
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(4 FeCr _{2} O _{4}+8 Na _{2} CO _{3}+7 O _{2} \rightarrow 8 Na _{2} CrO _{4}+2 Fe _{2} O _{3}\) \(+8 CO _{2}\) \(2 Na _{2} CrO _{4}+2 H ^{+} \rightarrow \underbrace{ Na _{2} Cr _{2} O _{7}}_{ B }+2 Na ^{+}+ H _{2} O\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- The decreasing order of reactivity of the following organic molecules towards \(AgNO\) \(_{3}\) solution is :
JEE Mains 2020 Medium - The density of \(\mathrm{NaOH}\) solution is \(1.2 \mathrm{gcm}^{-3} .\) The molality of this solution is \(....\,m\) (Round off to the NearestInteger) [Use:Atomicmasses:\(Na:23.0\,u \mathrm{O}: 16.0 \,\mathrm{u} \quad \mathrm{H}: 1.0 \,\mathrm{u}\), Density of \(\mathrm{H}_{2} \mathrm{O}: 1.0 \,\mathrm{~g} \,\mathrm{~cm}^{-3}\) ]JEE Mains 2021 Medium
-

A perfect gas \((0.1 \mathrm{~mol})\) having \(\overline{\mathrm{C}}_{\mathrm{v}}=1.50 \mathrm{R}\) (independent of temperature) undergoes the above transformation from point 1 to point 4. If each step is reversible, the total work done (w) while going from point 1 to point 4 is \((-)\) ________ J (nearest integer) \(\left[\right.\) Given : \(\left.\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]\)JEE Mains 2025 Medium - The shape/structure of \(\left[ XeF _{5}\right]^{-}\) and \(XeO _{3} F _{2}\)
respectively, are :JEE Mains 2020 Medium - \(2-\) hexene \(\xrightarrow[(ii)H_2O]{(i) O_3}\) Products The two products formed in above reaction are -JEE Mains 2023 Medium
- Lead storage battery contains \(38\,\%\) by weight solution of \(H _2 SO _4\). The van't Hoff factor is \(2.67\) at this concentration. The temperature in Kelvin at which the solution in the battery will freeze is \(..........\) (Nearest integer).Given \(K _{ f }=1.8\,K\, kg\, mol^{-1}\)JEE Mains 2023 Hard
More PYQs from JEE Mains
- A plane bisects the line segment joining the points \(( 1 , 2, 3)\) and \(( - 3, 4, 5)\) at right angles. Then this plane also passes through the pointJEE Mains 2018 Hard
- The number of points of discontinuity of the function \(f(\mathrm{x})=\left[\frac{\mathrm{x}^2}{2}\right]-[\sqrt{\mathrm{x}}], \mathrm{x} \in[0,4]\), where \([\cdot]\) denotes the greatest integer function is ________JEE Mains 2025 Easy
- A small uncharged conducting sphere is placed in contact with an identical sphere but having \(4 \times 10^{-8} \mathrm{C}\) charge and then removed to a distance such that the force of repulsion between them is \(9 \times 10^{-3} \mathrm{~N}\). The distance between them is (Take \(\frac{1}{4 \pi \epsilon_{\mathrm{o}}}\) as \(9 \times 10^9 \mathrm{in} \mathrm{SI}\) units)JEE Mains 2025 Hard
- A particle executes \(S.H.M.\) of amplitude A along \(x\)-axis. At \(t =0\), the position of the particle is \(x=\frac{A}{2}\) and it moves along positive \(x\)-axis the displacement of particle in time \(t\) is \(x=A \sin (\omega t+\delta)\), then the value \(\delta\) will beJEE Mains 2023 Medium
- Let \(b _{1} b _{2} b _{3} b _{4}\) be a \(4\)-element permutation with \(b _{i} \in\) \(\{1,2,3, \ldots \ldots . .100\}\) for \(1 \leq i \leq 4\) and \(b_{i} \neq b_{j}\) for \(i \neq j\), such that either \(b _{1}, b _{2}, b _{3}\) are consecutive integers or \(b _{2}, b _{3}, b _{4}\) are consecutive integers.JEE Mains 2022 Hard
- The distance \(x\) covered by a particle in one dimensional motion varies with time \(t\) as \(\mathrm{x}^{2}=\mathrm{at}^{2}+2 \mathrm{bt}+\mathrm{c.}\) If the acceleration of the particle depends on \(\mathrm{x}\) as \(\mathrm{x}^{-\mathrm{n}},\) where \(\mathrm{n}\) is an integer, the value of \(\mathrm{n}\) isJEE Mains 2020 Hard