JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The number of species from the following that are involved in \(\mathrm{sp}^3 \mathrm{~d}^2\) hybridization is :\(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}, \mathrm{SF}_6,\left[\mathrm{CrF}_6\right]^{3-},\left[\mathrm{CoF}_6\right]^{3-},\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}\) and \(\left[\mathrm{MnCl}_6\right]^3\).
- A \(5\)
- B \(6\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
In \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right]_6\right]^{3+}, \mathrm{Co}^{+3}:[\mathrm{Ar}] 3 \mathrm{~d}^6, \mathrm{NH}_3\) is S.F.L Hybridisation state of \(\mathrm{Co}^{3+}\) is \(\mathrm{d}^2 \mathrm{sp}^3\) In \(\mathrm{SF}_6\), Hybridisation state of sulphur is…
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