JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The type of hybridization and the magnetic property of \(\left[\mathrm{MnCl}_6\right]^{3-}\) are _______.
- A \(d^2 s p^3\), paramagnetic with four unpaired electrons
- B \(\mathrm{sp}^3 \mathrm{~d}^2\), paramagnetic with four unpaired electrons
- C \(\mathrm{d}^2 \mathrm{sp}^3\), paramagnetic with two unpaired electrons
- D \(\mathrm{sp}^3 \mathrm{~d}^2\), paramagnetic with two unpaired electrons
Answer & Solution
Correct Answer
(B) \(\mathrm{sp}^3 \mathrm{~d}^2\), paramagnetic with four unpaired electrons
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & {\left[\mathrm{MnCl}_6\right]^{3-} \text { contains } \mathrm{Mn}^{+3}} \\ & \mathrm{Mn}^{+3}:-[\mathrm{Ar}] 3 \mathrm{~d}^4 \\ & \text { Ligand } \Rightarrow \mathrm{Cl}^{-}(\mathrm{WFL})\end{aligned}\) \(\text { Hybridisation }=\mathrm{sp}^3 \mathrm{~d}^2\)…
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