JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The number of \(N\) atoms is \(681 \,g\) of \(C _{7} H _{5} N _{3} O _{6}\) is \(x \times 10^{21}\). The value of \(x\) is \(.....\) \(\left( N _{ A }=6.02 \times\right.\) \(10^{23}\, mol ^{-1}\) ) (Nearest Integer)
- A \(6418\)
- B \(5418\)
- C \(5118\)
- D \(5948\)
Answer & Solution
Correct Answer
(B) \(5418\)
Step-by-step Solution
Detailed explanation
M.M. of \(C _{7} H _{5} N _{3} O _{6}\) is \(84+5+42+96=227\) \(n _{ C _{7} H _{5} N _{3} O _{6}}=\frac{681}{227}=3\) \(n _{ N }=\frac{681}{227} \times 3=9 mol\) no. of \(N\) atoms \(=9 \times 6.02 \times 10^{23}\) \(=5418 \times 10^{21}\) \(\therefore\) The answer is \(5418 .\)
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