JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The number of complexes from the following with no electrons in the \(t_2\) orbital is _______. \(\mathrm{TiCl}_4,\left[\mathrm{MnO}_4\right]^{-},\left[\mathrm{FeO}_4\right]^{2-},\left[\mathrm{FeCl}_4\right]^{-},\left[\mathrm{CoCl}_4\right]^{2-}\)
- A \(3\)
- B \(1\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{TiCl}_4 \Rightarrow \mathrm{Ti}^{+4} \mathrm{e}^0 \mathrm{t}_2^0\) \(\mathrm{MnO}_4^{-} \Rightarrow \mathrm{Mn}^{+7} \mathrm{e}^0 \mathrm{t}_2^0\) \(\mathrm{FeO}_4^{2-} \Rightarrow \mathrm{Fe}^{+6} \mathrm{e}^2 \mathrm{t}_2^0\)…
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