JEE Mains · Chemistry · STD 11 -p-Block elements - I
Outermost electronic configuration of a group \(13\) element, \(E\), is \(4 \,\mathrm{~s}^{2}, 4 p^{1}\). The electronic configuration of an element of \(p\)-block period-five placed diagonally to element, \(E\) is :
- A \([\mathrm{Xe}]{5} \mathrm{~d}^{10} 6 \mathrm{~s}^{2} 6 \mathrm{p}^{2}\)
- B \([\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^{2} 5 \mathrm{p}^{2}\)
- C \([\mathrm{Kr}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{2} 4 \mathrm{p}^{2}\)
- D \( [Ar]\) \(3 d^{10} 4 s^{2} 4 p^{2}\)
Answer & Solution
Correct Answer
(B) \([\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^{2} 5 \mathrm{p}^{2}\)
Step-by-step Solution
Detailed explanation
The element \(\mathrm{E}\) is \(\mathrm{Ga}\) and the diagonal element of \(5^{\mathrm{th}}\) period is \({ }_{50} \mathrm{Sn}\) having outer electronic configuration will be \([\mathrm{Kr}] \,5 \mathrm{~s}^{2} \,4 \mathrm{~d}^{10}\, 5 \mathrm{p}^{2}\).
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