JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The formula of a gaseous hydrocarbon which requires \(6\) times of its own volume of \(O _{2}\) for complete oxidation and produces \(4\) times its own volume of \(CO _{2}\) is \(C _{ x } H _{ y }\). The value of \(y\) is ...... .
- A \(13\)
- B \(10\)
- C \(8\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
Combustion \(rx ^{ n }:\) \(C _{ x } H _{ y ( g )}+\left( x +\frac{ y }{4}\right) O _{2}( g ) \rightarrow \)\(x CO _{2}( g )+\frac{ y }{2} H _{2} O (\ell)\) \(V\,\quad\quad\quad\quad\quad6V\quad\quad\quad\quad\quad\quad-\)…
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