JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
\(1\,L,0.02\,M\) solution of \(\left[ Co \left( NH _3\right)_5 SO _4\right] Br\) is mixed with \(1\,L,0.02\,M\) solution of \(\left[ Co \left( NH _3\right)_5 Br _3\right] SO _4\). The resulting solution is divided into two equal parts (X) and treated with excess \(AgNO _3\) solution and \(BaCl _2\) solution respectively as shown below: \(1\,L\) Solution \(( X )+ AgNO _3\) solution (excess) \(\rightarrow Y\) \(1\,L\) Solution \(( X )+ BaCl _2\) solution (excess) \(\rightarrow Z\) The number of moles of \(Y\) and \(Z\) respectively are
- A \(0.02,0.02\)
- B \(0.01,0.01\)
- C \(0.02,0.01\)
- D \(0.01,0.02\)
Answer & Solution
Correct Answer
(B) \(0.01,0.01\)
Step-by-step Solution
Detailed explanation
\begin{array}{l}{\left[ Co \left( NH _3\right)_5 SO _4\right] Br + AgNO _3 \rightarrow AgBr \downarrow} \\ 0.01\, mol \qquad\quad \text { excess } \quad 0.01\,Mol \\ {\left[ Co \left( NH _3\right)_5 Br \right] SO _4+ BaCl _2 \rightarrow BaSO _4 \downarrow} \\ 0.01 mol…
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