JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The molar conductivity of a conductivity cell filled with \(10\) moles of \(20\,mL\,NaCl\) solution is \(\Lambda_{ m 1}\) and that of \(20\) \(moles\) another identical cell heaving \(80\) \(mL NaCl\) solution is \(\Lambda_{ m 2}\), The conductivities exhibited by these two cells are same.The relationship between \(\Lambda_{m 2}\) and \(\Lambda_{m 1}\) is\(........\)
- A \(\Lambda_{m 2}=2 \Lambda_{m 1}\)
- B \(\Lambda_{ m 2}=\Lambda_{ m 1} / 2\)
- C \(\Lambda_{ m 2}=\Lambda_{ m 1}\)
- D \(\Lambda_{ m 2}=4 \Lambda_{ m 1}\)
Answer & Solution
Correct Answer
(A) \(\Lambda_{m 2}=2 \Lambda_{m 1}\)
Step-by-step Solution
Detailed explanation
\(\Lambda_{ m }=\kappa \times \frac{1000}{ M }\) \(\Lambda_{ m } \propto \frac{1}{ M }\) \(\frac{\Lambda_{ m _{1}}}{\Lambda_{ m _{2}}}=\frac{ M _{2}}{ M _{1}}=\frac{\frac{20}{80}}{\frac{10}{20}}=\frac{1}{4} \times \frac{2}{1}=\frac{1}{2}\)…
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