JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The mole fraction of a solvent in aqueous solution of a solute is \(0.8\). The molality (in \(mol\, kg^{-1}\)) of the aqueous solution is
- A \(13.88 \times {10^{ - 2}}\)
- B \(13.88 \times {10^{ - 1}}\)
- C \(13.88\)
- D \(13.88 \times {10^{ - 3}}\)
Answer & Solution
Correct Answer
(C) \(13.88\)
Step-by-step Solution
Detailed explanation
\({X_{solvent}}\, = \,0.8\, = \,8/10\) \({N_{Total}}\, = \,10,\,{n_{solutent}}\, = \,8\,,\,{n_{solute}}\, = \,2\) Wt of solvent \( = \,8\, \times \,18\) Molality \( = \,\frac{{2 \times \,1000}}{{8 \times 18}}\)
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