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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The following results were obtained during kinetic studies of the reaction \(2A+B\) \(\to\) products
Experiment \([A]\) (in \(mol\, L^{-1})\) \([B]\) (in \(mol\, L^{-1})\) Initial rate of reaction (in \(mol\, L^{-1}\,min^{-1})\)
\(I\) \(0.10\) \(0.20\) \(6.93 \times {10^{ - 3}}\)
\(II\) \(0.10\) \(0.25\) \(6.93 \times {10^{ - 3}}\)
\(III\) \(0.20\) \(0.30\) \(1.386 \times {10^{ - 2}}\)
The time(in minutes) required to consume half of \(A\) is

  1. A \(5\)
  2. B \(10\)
  3. C \(1\)
  4. D \(100\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(R\,\, = \,k{[A]^x}\,{[B]^y}\) \(6.93\, \times \,{10^{ - 3}}\, = \,k\,{(0.1)^x}\,{(0.2)^y}\) ...... \((i)\) \(6.93\, \times \,{10^{ - 3}}\, = \,k\,{(0.1)^x}\,{(0.25)^y}\) ...... \((ii)\) \(1.386 \times \,{10^{ - 2}}\, = \,k\,{(0.2)^x}\,{(0.3)^y}\) . .... \((iii)\)…
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