JEE Mains · Chemistry · STD 11 - 2. structure of atom
The energy of one mole of photons of radiation of frequency \(2 \times 10^{12}\,Hz\) in \(Jmol ^{-1}\) is \(.....\)(Nearest integer) (Given: \(h =6.626 \times 10^{-34}\,JS\) \(\left. N _{ A }=6.022 \times 10^{23}\, mol ^{-1}\right)\)
- A \(796\)
- B \(798\)
- C \(797\)
- D \(785\)
Answer & Solution
Correct Answer
(B) \(798\)
Step-by-step Solution
Detailed explanation
For one photon \(E = hv\) For one mole photon, \(E=6 \cdot 023 \times 10^{23} \times 6.626 \times 10^{-34} \times 2 \times 10^{12}\)
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