JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
The disproportionation of \(MnO _{4}^{2-}\) in acidic medium resulted in the formation of two manganese compounds \(A\) and \(B\). If the oxidation state of \(Mn\) in \(B\) is smaller than that of \(A\), then the spin-only magnetic moment \((\mu)\) value of \(B\) in \(BM\) is \(.........\) (Nearest integer)
- A \(3\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
\(MnO _{4}^{2-} \stackrel{ H ^{+}}{\longrightarrow} MnO _{4}^{-}+ MnO _{2}\) No. of unpaired \(\overline{ e }=3\) \(\therefore \mu=\sqrt{15}=3.877\) Nearest Integer \(=4\)
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