JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Number of moles of methane required to produce \(22 \mathrm{~g} \mathrm{CO}_{2(\mathrm{~g})}\) after combustion is \(\mathrm{x} \times 10^{-2}\) moles. The value of \(\mathrm{x}\) is _______.
- A \(30\)
- B \(40\)
- C \(50\)
- D \(60\)
Answer & Solution
Correct Answer
(C) \(50\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\ell)}\) \(\mathrm{n}_{\mathrm{CO}_2}=\frac{22}{44}=0.5 \mathrm{moles}\) So moles of \(\mathrm{CH}_4\) required \(=0.5\) moles i.e.…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Dichromate ion is treated with base, the oxidation number of \(Cr\) in the product formed is .... .JEE Mains 2021 Easy
- Among the following compounds most basic amino acid isJEE Mains 2019 Hard
- The steam volatile compounds among the following are _______.
Choose the correct answer from the options given below :JEE Mains 2025 Medium - Given below are two statements:
Statement I: Sucrose is dextrorotatory. However sucrose upon hydrolysis gives a solution having mixture of products. This solution showing laevorotation.
Statement II: Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of glucose is more than the dextrorotation of fructose the resulting solution becomes laevorotatory.
In the light of the above statements, choose the correct answer from the options given below.JEE Mains 2026 Easy - Compound \(A\) gives \(D-\)Galactose and \(D-\)Glucose on hydrolysis. The compound \(A\) is:JEE Mains 2021 Medium
- The correct electronic configuration and spin only magnetic moment (BM) of \(Gd ^{3+}( Z =64)\), respectively, areJEE Mains 2020 Medium
More PYQs from JEE Mains
- In the given circuit below inductance values of \(L_1\), \(L_2\) and \(L_3\) are same. The magnetic energy stored in the entire circuit is \((U_t)\) and that stored in the \(L_2\) inductor is \((U_l)\). \(U_t / U_l\) is __________.
(Ignore the mutual inductance if any)
JEE Mains 2026 Medium - Number of compounds from the following which cannot undergo Friedel-Crafts reactions is _______.
[toluene, nitrobenzene, xylene, cumene, anline, chlorobenzene, \(m\)-nitroaniline, \(m\)-dinitrobenzene]JEE Mains 2024 Medium - A calorimeter of water equivalent \(20\, g\) contains \(180\, g\) of water at \(25^{\circ} C\). '\(m\)' grams of steam at \(100^{\circ} C\) is mixed in it till the temperature of the mixure is \(31^{\circ} C\). The value of \('m'\) is close to (Latent heat of water \(=540\) cal \(g ^{-1}\), specific heat of water \(=1\) cal \(g^{-1}{ }^{\circ} C ^{-1}\) )JEE Mains 2020 Medium
- \(\operatorname{Lim}_{x \rightarrow 0} \frac{e-(1+2 x)^{\frac{1}{2 x}}}{x}\) is equal to :JEE Mains 2024 Hard
- The density of a solid metal sphere is determined by measuring its mass and its diameter. The maximum error in the density of the sphere is \(\left(\frac{x}{100}\right) \% .\) If the relative errors in measuring the mass and the diameter are \(6.0 \%\) and \(1.5 \%\) respectively, the value of \(x\) isJEE Mains 2020 Hard
- The velocity (\(v\)) versus time (\(t\)) plot of a particle is shown in the figure, for a time interval of \(40\text{ s}\). The total distance travelled by the particle and the average velocity during this period are, respectively _______.
JEE Mains 2026 Easy