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JEE Mains · Chemistry · STD 11 - 2. structure of atom
The de-Broglie's wavelength of electron present in first Bohr orbit of \('H'\) atom is
- A \(4 \times 0.529\,\mathop A\limits^o \)
- B \(2\pi \times 0.529\,\mathop A\limits^o \)
- C \(\frac{{0.529}}{{2\pi }}\mathop A\limits^o \)
- D \(0.529\,\mathop A\limits^o \)
Answer & Solution
Correct Answer
(B) \(2\pi \times 0.529\,\mathop A\limits^o \)
Step-by-step Solution
Detailed explanation
First Bohr orbit of \(H\) atom has radius \(r = 0.529\,\mathop A\limits^o \) Also, the angular momentum is quantised. \(mvr = \frac{h}{{2\pi }}\) \(2\pi r = \frac{h}{{mv}} = \lambda \) \(\lambda = 2\pi \times 0.529\,\mathop A\limits^o \)
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