JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The crystal Field stabilization Energy \((CFSE)\) of \(\left[ CoF _{3}\left( H _{2} O \right)_{3}\right]\left(\Delta_{0}< P \right)\) is \(:-\)
- A \(-0.8 \Delta_{0}\)
- B \(-0.4 \Delta_{0}+ p\)
- C \(-0.8 \Delta_{0}+2 P\)
- D \(-0.4 \Delta_{0}\)
Answer & Solution
Correct Answer
(D) \(-0.4 \Delta_{0}\)
Step-by-step Solution
Detailed explanation
\(\left[ CoF _{3}\left( H _{2} O \right)_{3}\right] \quad \Delta_{0}< P\) Means all ligands behaves as weak field ligands \(=[-0.4 \times 4+0.6 \times 2] \Delta_{0}\) \(=[-1.6+1.2] \Delta_{0}\) \(=\left[-0.4 \Delta_{0}\right]\)
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