JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
If the activation energy of a reaction is \(80.9 \,kJ \,mol^{-1},\) the fraction of molecules at \(700 \,K\), having enough energy to react to form products is \(e ^{-x}\). The value of \(x\) is ....... .
(Rounded off to the nearest integer) \(\left[\right.\) Use \(\left. R =8.31 \,J \,K ^{-1} \,mol ^{-1}\right]\)
- A \(17\)
- B \(16\)
- C \(14\)
- D \(15\)
Answer & Solution
Correct Answer
(C) \(14\)
Step-by-step Solution
Detailed explanation
Fraction of molecules to have enough energy to react \(= e ^{- E / RT }\) So, \(x=\frac{E_{a}}{R T}\) \(=\frac{80.9 \times 10^{3}}{8.31 \times 700}\)\(=13.9\)
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