JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The d-electronic configuration of \(\left[ CoCl _4\right]^{2-}\) in tetrahedral crystal field is \(e ^{ m } t _2\). Sum of ' \(m\) ' and number of unpaired electrons is \(.............\).
- A \(6\)
- B \(5\)
- C \(7\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\(Co ^{2+}: 3 d ^7 4 s ^0, Cl ^{-}: WFL\) Configuration \(e ^4 t _2^3: m =4\) Number of unpaired electrons \(=3\) So, answer \(=7\)
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