JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The correct order of the calculated spin-only magnetic moments of complexs \((A)\) to \((D)\) is \((A)\) \(\mathrm{Ni}(\mathrm{CO})_{4}\) \((B)\) \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{2}\) \((C)\) \(\mathrm{Na}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]\) \((D)\) \(\mathrm{PdCl}_{2}\left(\mathrm{PPh}_{3}\right)_{2}\)
- A \((\mathrm{A}) \approx(\mathrm{C}) \approx(\mathrm{D}) < (\mathrm{B})\)
- B \((\mathrm{A}) \approx(\mathrm{C}) < (\mathrm{B}) \approx(\mathrm{D})\)
- C \((\mathrm{C}) < (\mathrm{D}) < (\mathrm{B}) < (\mathrm{A})\)
- D \((\mathrm{C}) \approx(\mathrm{D}) < (\mathrm{B}) < (\mathrm{A})\)
Answer & Solution
Correct Answer
(A) \((\mathrm{A}) \approx(\mathrm{C}) \approx(\mathrm{D}) < (\mathrm{B})\)
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right] \quad \mu_{\mathrm{m}}=0 \mathrm{B}. \mathrm{M}\) \({\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Cl}_{2}}\quad {\mu_{\mathrm{m}}=2.8 \mathrm{B} . \mathrm{M}}\)…
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