JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
\([\mathrm{Pd}(\mathrm{F})(\mathrm{Cl})(\mathrm{Br})(\mathrm{I})]^{2-}\) has \(n\) number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy \([CFSE]\) of \([Fe(CN)_6]^{\mathrm{n}-6},\) respectively, are [Note : Ignore the pairing energy]
- A \(2.84\; \mathrm{BM}\) and \(-1.6 \Delta_{0}\)
- B \(1.73\; \mathrm{BM}\) and \(-2.0 \Delta_{0}\)
- C \(0\; \mathrm{BM}\) and \(-2.4 \Delta_{0}\)
- D \(5.92\; \mathrm{BM}\) and \(0\)
Answer & Solution
Correct Answer
(B) \(1.73\; \mathrm{BM}\) and \(-2.0 \Delta_{0}\)
Step-by-step Solution
Detailed explanation
\([\mathrm{Pb}(\mathrm{F})(\mathrm{Cl})(\mathrm{Br})(\mathrm{I})]^{2-}\) have three geometrical isomer so formula for \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{\mathrm{n}-6}\) is \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}\) and \(\mathrm{CFSE}\) for this complex is…
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