JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{3} \quad \mathrm{~K}_{\mathrm{c}}=1.844\) \(3.0\) \(moles\) of \(\mathrm{PCl}_{5}\) is introduced in a \(1\, \mathrm{~L}\) closed reaction vessel at \(380\, \mathrm{~K}\). The number of moles of \(\mathrm{PCl}_{5}\) at equilibrium is \(.....\,\times 10^{-3}\). (Round off to the Nearest Integer)
- A \(1500\)
- B \(1292\)
- C \(1400\)
- D \(5123\)
Answer & Solution
Correct Answer
(C) \(1400\)
Step-by-step Solution
Detailed explanation
\(\mathrm{PCl}_{5(g)} \rightleftharpoons \mathrm{PCl}_{3(g)}+\mathrm{Cl}_{2(g)} \quad \mathrm{K}_{2}=1.844\) \(\mathrm{t}=0\quad3\) \(moles\) \(\mathrm{t}=\infty \quad \mathrm{x} \quad \mathrm{x}\)…
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