JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Molal depression constant for a solvent is \(4.0\, K\, Kg\, mol^{-1}\). The depression in the freezing point of the solvent for \(0.03\, mol\, kg^{-1}\) solution of \(K_2SO_4\) is .............. \(\mathrm{K}\) (Assume complete dissociation of the electrolyte)
- A \(0.12\)
- B \(0.36\)
- C \(0.18\)
- D \(0.24\)
Answer & Solution
Correct Answer
(B) \(0.36\)
Step-by-step Solution
Detailed explanation
\({K_f}\, = \,4\,K\,Kg\,mo{l^{ - 1}}\) \(i\, = \,3\) Molality \(=\,0.03\) \(\Delta {T_f}\, = \,i{K_f}m\) \( = \,3(4)\,(0.03)\) \(\Delta {T_f}\, = \,0.36\,K\)
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