JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
An aqueous solution of HCl with pH 1.0 is diluted by adding equal volume of water (ignoring dissociation of water). The pH of HCl solution would _______.
(Given \(\log 2=0.30)\)
- A reduce to \(0.5\)
- B increase to \(1.3\)
- C remain same
- D increase to \(2\)
Answer & Solution
Correct Answer
(B) increase to \(1.3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{HCl}_{(\mathrm{aq})} \mathrm{pH}=1 ;\left[\mathrm{H}^{+}\right]=10^{-1}\) If equal volume of water is added concentration will become half \(\begin{aligned}& {\left[\mathrm{H}^{+}\right]_{\mathrm{sol}}=\frac{10^{-1}}{2}} \\& \mathrm{pH}=1.3\end{aligned}\)
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