JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Millimoles of calcium hydroxyide required to produce \(100\,mL\) of the aqueous solution of \(pH \,12\) is \(x \times 10^{-1}\). The value of \(x\) is \(..............\). (Nearest integer).Assume complete dissociation.
- A \(5\)
- B \(4\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(\because pH =12\) \(\therefore\left[ H ^{+}\right]=10^{-12}\,M\) \(\therefore\left[ OH ^{-}\right]=10^{-2}\,M\) \(\therefore\left[ Ca ( OH )_2\right]=5 \times 10^{-3}\,M\) \(5 \times 10^{-3}=\frac{\text { milli moles of } Ca ( OH )_2}{100\,mL }\)…
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