JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
In the reaction,
\(2Al(s)+6HCl(aq)\rightarrow2Al^{3+}(aq)+6Cl^{-}(aq)+3H_{2}(g)\)
- A 11.2 L \(H_{2}(g)\) at STP is produced for every mole of HCl consumed.
- B 67.2 L \(H_{2}(g)\) at STP is produced for every mole of Al that reacts.
- C 12 L \(HCl(aq)\) is consumed for every 6L \(H_{2}(g)\) produced.
- D 33.6 L \(H_{2}(g)\) is produced regardless of temperature and pressure for every mole of Al that reacts.
Answer & Solution
Correct Answer
(A) 11.2 L \(H_{2}(g)\) at STP is produced for every mole of HCl consumed.
Step-by-step Solution
Detailed explanation
\(2Al (s) + 6HCl (aq) \rightarrow 2Al^{3+} (aq) + 6Cl^{-} (aq) + 3H_{2}(g)\) Mole of \(H_{2}\) produced \(=2 \times\) mole of HCl used \(=\frac{2}{3} \times\) mole of Al used
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